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the common tangent touching hyperbola (x^2)/9 - (y^2)/16=1 and (x^2)/16 - (y^2)/9=-1. plz clear my doubt as soon as possible. thans....

the common tangent touching hyperbola (x^2)/9 - (y^2)/16=1


and (x^2)/16 - (y^2)/9=-1.


plz clear my doubt as soon as possible.


thans....

Grade:

1 Answers

k sesi preetam
7 Points
7 years ago

consider the equations of  tangents to both the hyperbola in the slope form which is for the first hyperbola y=mx+sqrt(a^2*m^2-b^2) and for the second one it is y=mx +sqrt(a^2+b^2*m^2) where a=3 b=4.. As it is a common tangent the slope is m and for both of them the y intercept has to be equal. Hence on equating we get the value of m which is the slope of the tangent and hence we get the required tangent.

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