A(1,3) and C(-2/5,-2/5) are the vertices of a triangle ABC and the equation of angle bisector of angle(ABC) is x+y=2.What is the equation of side BC and AB.

In a triangle ABC image of A in angle bisector of angle(ABC) lies on BC and of C on AB 

Image of A in x+y-2=0 is (-1,1) which lies on BC using 2 point form it will be 7x+3y+4=0

similarly AB can be found out.

cool concept