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if (a,1/a),(b,1/b)&(c,1/c)are the vertices of a triangle,(a,b) are roots of x2-6p1x+2=0,(b,c)roots of x2-6p2x+3=0&(c,a)roots of x2-6p3x+6=0.p1,p2,p3being positive,find p1,p2,p3¢roid of triangle.
Dear jagannath
(a,b) are roots of x2-6p1x+2=0
a+b=6p1 ............1
ab=2 .............2
(b,c)roots of x2-6p2x+3=0
b+c=6p2............3
bc=3..........4
(c,a)roots of x2-6p3x+6=0
c+a=6p3 .............5
ca=6 .............6
from equation 2,4,6
(ab)(bc)=ca
b=1
and a=2
c=3
so P1 =1/2
p2 =2/3
P3=5/6
now centroid ={(1+2+3)/3 ,(1/2 +1/1 +1/3 )/3 }
(2,11/18)
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