Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A circle having its centre in the first quadrant touches the y axis at point (0,2) and passes through the point (1,0) . find the equation of circle.

A circle having its centre in the first quadrant touches  the y axis at point (0,2) and passes through the point (1,0) . find the equation of circle.

Grade:12th pass

2 Answers

Himanshu Sharma
31 Points
8 years ago

look

since circle touches y axis at (0,2)

hence perpendicular from this point passes through centre as y axis is tangent to it..

hence coordinate of circle would be (a,2)

now its disatnce from (0,2)and (1,0) is equal as its the radius itself

hence √(a-0)^2+(2-2)^2=√(a-1)^2+(2-0)^2

a^2=a^2+1-2a+4

a=5/2

hence radius =5/2

equation =(x-5/2)^2+(y-2)^2=(5/2)^2

 


ankitesh gupta
63 Points
8 years ago

 

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ APPROVE THE ANSWER IF IT HELPED YOU BY CLICKING THE YES BUTTON.................................Smile

1517_74742_16.jpg

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free