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`        let ABC be a triangle right angled at B.Let AD be the angle bisector of A.suppose AC=6cm and the area of the triangle ADC is 10cm^2, wat is length of BD?`
7 years ago

```							let AB = a
BC = b
pythagoras thm
a^2 + b^2 = 36
also area 1/2ab = 10    => b=20/a  put in above eqn
a^2 + 400/a^2 = 36
a^4 - 36a^2 +400 = 0
discriminant 36*36 - 4*400 = -304 negative which give imaginary values
```
7 years ago
```							ans:3.33cm

let AB=h     BD=l   DC=x AC=6cm
DC is base BUt Height Would be AB
Hence area would be 1/2hx=10
hx=20

but as AD is internal angle bisector   then using internal angle bisector theorem
AB/AC=BD/DC
AB.dC=BD.AC
hx=6l
but hx=20
hence l=10/3=3.33cm
```
7 years ago
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