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The equation x^2/(2-k)+y^2/(k-5)+1=0 represents an ellipse , if (a)k (b)k (c)2 (d)k 5
answer x^2/(2-k)+y^2/(k-5)=-1 x^2/(k-2)+y^2/(5-k)=1 where "a"is the semi major axis a^2=k-2 k=a^2+2 (k>2) "b" is semi minor axis b^2=5-k k=5-b^2 (k<5) so answer is (a)
answer
x^2/(2-k)+y^2/(k-5)=-1
x^2/(k-2)+y^2/(5-k)=1
where "a"is the semi major axis a^2=k-2
k=a^2+2 (k>2)
"b" is semi minor axis b^2=5-k
k=5-b^2 (k<5)
so answer is (a)
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