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draw the graph of the equation x^2+y^2+4x+6y-3=0 and x^2+y^2+12x+14y+60=0. then find the equation of the radical axis and draw the axis.
since the eqn of the radical axis is S1 - S2 = 0
SUB tracting the eqn.s of the circles =
x^2+y^2+4x+6y-3 - (x^2+y^2+12x+14y+60)
-8x -8y -63 = 0
we get, 8x + 8y + 63 = 0
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