Create your Smart Home App in the Free Webinar on Home Automation. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on App Development Learn to create your own Smart Home App
16th Jan @ 5:00PM for Grade 1 to 10
Sit and relax as our customer representative will contact you within 1 business day
the sides of a right angle triangle are a,a+d,a+2d with a and d both positive.the ratio of a to d a)1:2 b)1:3 c)3:1 d)5:2
given that tshe sides are a,a+d,a+2d let a+2d be the side opposite to the hypotenuse let the angles be p,90-p,90 we apply sine rule a/sin(p)= a+d/sin(90-p)=a+2d/sin90 a/sin(p)=a+2d , a+d/sin(90-p)=a+2d {sin(90-p)=cosp} sin(p)=a/a+2d , cos(p)=a+d/a+2d we know that sin^2(p)+cos^2(p)=1 (a/a+2d)^2+(a+d/a+2d)^2=1 solving this we get (a+d)^2+(a)62=(a+2d)^2 a^2+d^2+2.a.d=a^2+4.d^2+4.a.d 0=a^2-2.a.d-3.d^2 its quadratic equation in a here the roots fot a is 3d a=3d a/d=1:3
given that tshe sides are a,a+d,a+2d
let a+2d be the side opposite to the hypotenuse
let the angles be p,90-p,90
we apply sine rule
a/sin(p)= a+d/sin(90-p)=a+2d/sin90
a/sin(p)=a+2d , a+d/sin(90-p)=a+2d {sin(90-p)=cosp}
sin(p)=a/a+2d , cos(p)=a+d/a+2d
we know that sin^2(p)+cos^2(p)=1
(a/a+2d)^2+(a+d/a+2d)^2=1
solving this we get
(a+d)^2+(a)62=(a+2d)^2
a^2+d^2+2.a.d=a^2+4.d^2+4.a.d
0=a^2-2.a.d-3.d^2
its quadratic equation in a
here the roots fot a is 3d
a=3d
a/d=1:3
c is the answer .3:1
answer is (c) i.e. 3:1 Solution: Applying Pythagoras Theorem, we get, (a+2d)2=a2+(a+d)2 => a2+4d2+4ad=a2+a2+d2+2ad => 3d2+2ad-a2=0 => (d+a)(3d-a)=0 neglecting (d+a)=0, by solving for (3d-a)=0, we get a:d=3:1
answer is (c) i.e. 3:1
Solution: Applying Pythagoras Theorem,
we get, (a+2d)2=a2+(a+d)2
=> a2+4d2+4ad=a2+a2+d2+2ad
=> 3d2+2ad-a2=0
=> (d+a)(3d-a)=0
neglecting (d+a)=0, by solving for (3d-a)=0, we get a:d=3:1
Let a+2d be the side opposite to the hypotenuselet the angles be p,90-p,90we apply sine rulea/sin(p)= a+d/sin(90-p)=a+2d/sin90a/sin(p)=a+2d , a+d/sin(90-p)=a+2d {sin(90-p)=cosp} sin(p)=a/a+2d , cos(p)=a+d/a+2dwe know that sin^2(p)+cos^2(p)=1(a/a+2d)^2+(a+d/a+2d)^2=1solving this we get(a+d)^2+(a)62=(a+2d)^2a^2+d^2+2.a.d=a^2+4.d^2+4.a.d0=a^2-2.a.d-3.d^2its quadratic equation in ahere the roots fot a is 3da=3da/d=1:3
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -