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P(1,3) is the image of Q(-3,1) in the line L. The equation to the line L is ? P(1,3) is the image of Q(-3,1) in the line L. The equation to the line L is ?
P(1,3) is the image of Q(-3,1) in the line L. The equation to the line L is ?
Dear Anand, Since P is image of Q by reflection on line L. mid point of P and Q is on line L and the line is also perpendicular to the line joining points P and Q which is the general concept in finding line of reflection mid point of p(1,3) and q(-3,1) is M[(1-3)/2,(3+1)/2]=>M(-1,2) slope of line joining pq = (1-3)/(-3-1) = -2/-4 =1/2 let, slope of our line L is m => mX1/2 = -1 =>m = -2 therefore, equation of the line is, y-y1 = m(x-x1) in our case x1,y1 = (-1,2) => y-2 = -2(x+1) =>y = -2x Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Anand !!!Regards,Askiitians ExpertsRohith Gandhi P
Dear Anand,
Since P is image of Q by reflection on line L. mid point of P and Q is on line L and the line is also perpendicular to the line joining points P and Q which is the general concept in finding line of reflection
mid point of p(1,3) and q(-3,1) is M[(1-3)/2,(3+1)/2]=>M(-1,2)
slope of line joining pq = (1-3)/(-3-1) = -2/-4 =1/2
let, slope of our line L is m
=> mX1/2 = -1 =>m = -2
therefore, equation of the line is,
y-y1 = m(x-x1)
in our case x1,y1 = (-1,2)
=> y-2 = -2(x+1)
=>y = -2x
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Anand !!!Regards,Askiitians ExpertsRohith Gandhi P
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