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P(1,3) is the image of Q(-3,1) in the line L. The equation to the line L is ?
Dear Anand,
Since P is image of Q by reflection on line L. mid point of P and Q is on line L and the line is also perpendicular to the line joining points P and Q which is the general concept in finding line of reflection
mid point of p(1,3) and q(-3,1) is M[(1-3)/2,(3+1)/2]=>M(-1,2)
slope of line joining pq = (1-3)/(-3-1) = -2/-4 =1/2
let, slope of our line L is m
=> mX1/2 = -1 =>m = -2
therefore, equation of the line is,
y-y1 = m(x-x1)
in our case x1,y1 = (-1,2)
=> y-2 = -2(x+1)
=>y = -2x
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