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THE CIRCLE X2 + Y2 =16 TOUCHES THE SIDES BC,CA AND AB OF TRIANGLE ABC REPECTIVELY AT D,E AND F.IF THE LENGTH BD,CE AND AF ARE CONSECUTIVE INTEGERS THEN THE LARGESTSIDE OF THE TRIANGLE IS EQUAL TO
let x be an intezer, then its consecutive intezets are x+1 , x+2
Since OB,OA,OC are internal bisectors of each angle , BD=BF , DC=CE , AF=AE
so, the sides are 2x+1 ,2x+2, 2x+3
for x=5 , the sides are 11,12,13
for x=6 , the sides are 13,14,15
hence option A,C
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regards
Ramesh
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