×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

solve- if one vertex of an equilateral triangle of side "a" lies at origin and other lies on the line x=(square root of 3)*y the third vertex is..


8 years ago

Jitender Singh
IIT Delhi
158 Points
							Ans: y-axisSol:First vertex lie at the origin O (0, 0). The second vertex A lie on th line$y = \frac{1}{\sqrt{3}}x$Slope of this line is 30 & portion of length ‘a’ of this line is one side of tringle OAB. So the slope of one other side should be 90 as angle b/w sides of OAB should be 60. So the third vertex should lie on this sides which is y-axis. We have$B (\frac{\sqrt{3}a}{2}, \frac{a}{2})$$C (0, a)$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 53 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions