badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade:

                        

solve- if one vertex of an equilateral triangle of side "a" lies at origin and other lies on the line x=(square root of 3)*y the third vertex is..

8 years ago

Answers : (1)

Jitender Singh
IIT Delhi
askIITians Faculty
158 Points
							
Ans: y-axis
Sol:
First vertex lie at the origin O (0, 0). The second vertex A lie on th line
y = \frac{1}{\sqrt{3}}x
Slope of this line is 30 & portion of length ‘a’ of this line is one side of tringle OAB. So the slope of one other side should be 90 as angle b/w sides of OAB should be 60. So the third vertex should lie on this sides which is y-axis. We have
B (\frac{\sqrt{3}a}{2}, \frac{a}{2})
C (0, a)
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 53 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details