Analytical Geometry> straight lines...

solve- if one vertex of an equilateral triangle of side a lies at origin and other lies on the line x=(square root of 3)*y the third vertex is..

shivang raichand , 12 Years ago

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1 Answers

Jitender Singh

Last Activity: 10 Years ago

Ans: y-axis

Sol:

First vertex lie at the origin O (0, 0). The second vertex A lie on th line

$y = \frac{1}{\sqrt{3}}x$

Slope of this line is 30 & portion of length ‘a’ of this line is one side of tringle OAB. So the slope of one other side should be 90 as angle b/w sides of OAB should be 60. So the third vertex should lie on this sides which is y-axis. We have

$B (\frac{\sqrt{3}a}{2}, \frac{a}{2})$

$C (0, a)$

Thanks & Regards

Jitender Singh

IIT Delhi

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Analytical Geometry> straight lines...

solve- if one vertex of an equilateral triangle of side a lies at origin and other lies on the line x=(square root of 3)*y the third vertex is..

shivang raichand , 12 Years ago

Jitender Singh

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