Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
the curve describes parametrically by x = t^2 +t+1 and y = t^2-t+1 represents A) STRAIGHT LINE B) ELLIPSE C) HYPERBOLA D) PARABOLA the curve describes parametrically by x = t^2 +t+1 and y = t^2-t+1 represents A) STRAIGHT LINE B) ELLIPSE C) HYPERBOLA D) PARABOLA
Hi raman x = t^2 +t+1 and y = t^2-t+1 just simply aubtract x-y =2t or t=(x-y)/2 Nor put yalue of t in any one of above equation y=[(x-y)/2]2 - (x-y)/2 +1 simplify x2+y2 -2xy-2x-2y +4 =0 compair this equation with the general equation Δ not equal to zero and h2 -ab=0 so its represent parabola Regards Badiuddin
Hi raman
x = t^2 +t+1 and y = t^2-t+1
just simply aubtract
x-y =2t
or t=(x-y)/2
Nor put yalue of t in any one of above equation
y=[(x-y)/2]2 - (x-y)/2 +1
simplify
x2+y2 -2xy-2x-2y +4 =0
compair this equation with the general equation
Δ not equal to zero
and h2 -ab=0
so its represent parabola
Regards
Badiuddin
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -