Coordinates of the foot of te perpendicular drawn from (0,0) to the line joining (acos Φ, a sinΦ) and ( acosβ, a sinβ) are

(a) (a/2, b/2) (b) (a/2(cosΦ + cosβ), a/2 (sinΦ + sinβ)) (c) (cos ((Φ+β)/2), sin ((Φ+β)/2)) (d) (0, b/2)

Explain pls.

Dear Aditi,

The two points 

Thus the foot of perpendicular must lie on the mid point of the two points.

Best Of luck

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