cartesian coordinates

Question

If the vertices of a triangle are (am12, 2am1), ??(am22, 2am2) (am32, 2am3), then its area is(a) a(m2-m3)(m3-m1)(m1-m2)(b) (m2-m3)(m3-m1)(m1-m2)(c) a2(m2-m3)(m3-m1)(m1-m2)(d) a(m2+m3)(m3+m1)(m1+m2)Explain pls.

Aman Bansal · Accepted Answer

Dear Aditi,If the coordinates of the vertices are (x1,y1), (x2,y2), and (x3,y3), then the area is given by the formulaA = (1/2) det[(x1,y1,1), (x2,y2,1), (x3,y3,1)].Best Of luckCracking IIT just got more exciting,It&rsquo;s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role.ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and winby answering queries in the discussion forums.Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simpleto download the toolbar&hellip;.So start the brain storming&hellip;. become a leader with Elite Expert League ASKIITIANSThanksAman BansalAskiitian Expert

Analytical Geometry> cartesian coordinates...

If the vertices of a triangle are (am12, 2am1), ??(am22, 2am2) (am32, 2am3), then its area is(a) a(m2-m3)(m3-m1)(m1-m2)(b) (m2-m3)(m3-m1)(m1-m2)(c) a2(m2-m3)(m3-m1)(m1-m2)(d) a(m2+m3)(m3+m1)(m1+m2)Explain pls.

Aditi Bhatnagar , 12 Years ago

Aman Bansal

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Analytical Geometry> cartesian coordinates...

If the vertices of a triangle are (am12, 2am1), ??(am22, 2am2) (am32, 2am3), then its area is(a) a(m2-m3)(m3-m1)(m1-m2)(b) (m2-m3)(m3-m1)(m1-m2)(c) a2(m2-m3)(m3-m1)(m1-m2)(d) a(m2+m3)(m3+m1)(m1+m2)Explain pls.

Aditi Bhatnagar , 12 Years ago

Aman Bansal

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