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The incentre of the triangle formed by (1,2),(3,4) and (2,3) is
a) (2,3) b) (- 2,3) c) (2,-3) d) none
Please explain.
Hi Halak Sheth,
The answer is option (a) .
It is nothing but the centroid of of the triangle.
Just substitute the coordinates in the formula,and thus solved.
Hope that helps!!
Hi Halak,
The place from where you have taken this question has some error.
Note that (1,2) (2,3) and (3,4) lie on the same straight line y=x+1 and hence they are points on a stright line, and so they cannot form a triangle.
Hence there will be no incentre.
The answer should be none. Option (D).
But if the answer in the source from where you took this is given as the midpoint of the points (1,2) and (3,4), then it is wrong.
So option (A) is not the right answer.
Hope this helps.
Best Regards,
Ashwin (IIT Madras).
Hi Halek Sheth,
I made a mistake,sorry.I didnt look at the question correctly.Since it mentioned as triangle,i took it a striangle,but actually its wrong.
Its actually collinear points.C is the mid point of AB.
Thus the answer is option (d).
(Ashwin(sir):Na answer panrathe eppayachu tha,adhiliyum eppidiya anyaayama manna alli podriya....y dis kolaveri? :) )
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