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If two of the lines represented by the equation y3+axy2+(a2+6)x2y+2x3=0 are perpendicular to each other,then a is equal to
a.-2
b.-4
c.2
d.4
Hi Menka,
The system of lines passes through the origin (as is evident from the given eqn).
So use y=mx, you'd get a cubic in "m". For which m1,m2,m3 are the roots.
Find:
1) m1m2m3
2) m1m2 + m2m3 + m3m1
3) m1+m2+m3
from the equation, and use m1m2=-1.
And using this condition, elimintae m1,m2,m3 from the three equations, and find "a".
Best Regards,
Ashwin (IIT Madras)
dUDE QUESTION IS WRONG,PAIR OF LINES ARE OF 2 DEGREES .THIS CURVE DOES NOT REPRESENT 2 LINES.
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