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9 years ago

Hi Sarthak,

Consider A(x1,y1) to be the point on the curve C1 andB(x2,y2) to be the point on the curve C2.

A will satisfy C1, B will satisfy C2.From these two you will get relation between x1 and y1

and also between x2 and y2.

Now distance between A and B = distance formula = √[(x1-x2)Now this distance has to be minimised based on the relation between x1,y1 and relation between x2,y2.

This is the standard aproach.But based on specific questions(where curves are say two circles), you can use different approaches like visualising the two circles, and the two points on the circle should be on the line joining the centres.

Different approaches can be used for different curves.

All the best.Regards,

Ashwin (IIT Madras).

9 years ago

Dear Sarthak,

shortest distance b/w two curves is the distance along their common normal.....so find the eqn of common norma at a point of any curve and then solve it wid another curve u will get two points of intersection,,,,now calculate distance using distance formula

Best Of Luck...!!!!

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4 years ago

3 years ago

3 years ago

by drawing normal and passing it from another curve, thus if two curvs are circle and parabola resp. then you can take eq of normal which passes through the circle ,hence equate distance (radius)

9 months ago

Please find below the solution to your problem.

Consider A(x1,y1) to be the point on the curve C1 and B(x2,y2) to be the point on the curve C2.

A will satisfy C1, B will satisfy C2.

From these two you will get relation between x1 and y1 and also between x2 and y2.Now distance between A and B

= distance formula

= √[(x1-x2)2+(y1-y2)2].

Now this distance has to be minimised based on the relation between x1,y1 and relation between x2,y2.

Thanks and Regards

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