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the points (0,8/3), (1,3) and (82,30) are vertices of which type of triangle ( acute ,obtuse,right, isoseles etc)
the simplest way to determine the nature of the triangle is to compute the sides of it square of one side ,a^2 = { (0-1)^2 + (8/3 -3)^2 } = 10/9 =1.11 b^2 = { (82-1)^2 + (30 -3)^2 } = 7290 c^2 = { (82-0)^2 + (30 -8/3)^2 } =7471.11 it shows that , c^2 > a^2 + b^2 so the tiangle would be acute
the simplest way to determine the nature of the triangle is to compute the sides of it
square of one side ,a^2 = { (0-1)^2 + (8/3 -3)^2 } = 10/9 =1.11
b^2 = { (82-1)^2 + (30 -3)^2 } = 7290
c^2 = { (82-0)^2 + (30 -8/3)^2 } =7471.11
it shows that , c^2 > a^2 + b^2
so the tiangle would be acute
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