Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
the points (0,8/3), (1,3) and (82,30) are vertices of which type of triangle ( acute ,obtuse,right, isoseles etc) the points (0,8/3), (1,3) and (82,30) are vertices of which type of triangle ( acute ,obtuse,right, isoseles etc)
the points (0,8/3), (1,3) and (82,30) are vertices of which type of triangle ( acute ,obtuse,right, isoseles etc)
the simplest way to determine the nature of the triangle is to compute the sides of it square of one side ,a^2 = { (0-1)^2 + (8/3 -3)^2 } = 10/9 =1.11 b^2 = { (82-1)^2 + (30 -3)^2 } = 7290 c^2 = { (82-0)^2 + (30 -8/3)^2 } =7471.11 it shows that , c^2 > a^2 + b^2 so the tiangle would be acute
the simplest way to determine the nature of the triangle is to compute the sides of it
square of one side ,a^2 = { (0-1)^2 + (8/3 -3)^2 } = 10/9 =1.11
b^2 = { (82-1)^2 + (30 -3)^2 } = 7290
c^2 = { (82-0)^2 + (30 -8/3)^2 } =7471.11
it shows that , c^2 > a^2 + b^2
so the tiangle would be acute
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -