the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is

1) (x-1)^2 + (y-1)^2=16

2) (x-2)^2 + (y+2)^2=4

3) (x+2)^2 + (y+2)^2=4

4) (x-2)^2 + (y-2)^2=4

as circle is in 1st quadrant,thus the coordinates of circle are positive.

for area = 4*3.14, radius =2

so clearly visibl option is 4.

hey rani ..

 if the circle is touching both the axis i.e

area = 3.14 x r² 

thus, 3.14 x r²  = 4 x 3.14

 r= 2 (as it is in first quadrant)

Thus the answer (4) is correct...