the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is

1) (x-1)^2 + (y-1)^2=16

2) (x-2)^2 + (y+2)^2=4

3) (x+2)^2 + (y+2)^2=4

4) (x-2)^2 + (y-2)^2=4

Question

the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is 1) (x-1)^2 + (y-1)^2=16 2) (x-2)^2 + (y+2)^2=4 3) (x+2)^2 + (y+2)^2=4 4) (x-2)^2 + (y-2)^2=4

Sanjeev Malik IIT BHU · Answer

as circle is in 1st quadrant,thus the coordinates of circle are positive. for area = 4*3.14, radius =2 so clearly visibl option is 4.

sushant singh · Answer

hey rani .. if the circle is touching both the axis i.e area = 3.14 x r 2 thus, 3.14 x r 2 = 4 x 3.14 r= 2 (as it is in first quadrant) Thus the answer (4) is correct...

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is 1) (x-1)^2 + (y-1)^2=16 2) (x-2)^2 + (y+2)^2=4 3) (x+2)^2 + (y+2)^2=4 4) (x-2)^2 + (y-2)^2=4

the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is

1) (x-1)^2 + (y-1)^2=16

2) (x-2)^2 + (y+2)^2=4

3) (x+2)^2 + (y+2)^2=4

4) (x-2)^2 + (y-2)^2=4

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Analytical Geometry

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is 1) (x-1)^2 + (y-1)^2=16 2) (x-2)^2 + (y+2)^2=4 3) (x+2)^2 + (y+2)^2=4 4) (x-2)^2 + (y-2)^2=4

the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is 1) (x-1)^2 + (y-1)^2=16 2) (x-2)^2 + (y+2)^2=4 3) (x+2)^2 + (y+2)^2=4 4) (x-2)^2 + (y-2)^2=4

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Analytical Geometry

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

the equation of a circle whose area is 4*3.14 lying in the 1st quadrant and touching both the axis is

1) (x-1)^2 + (y-1)^2=16

2) (x-2)^2 + (y+2)^2=4

3) (x+2)^2 + (y+2)^2=4

4) (x-2)^2 + (y-2)^2=4