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The inverse point of (-2,3) with rspect to circle x^2+y^2-4x-6y+9=0 is
a)(1,1)
b)!1,2)
c)(1,3)
d)(2,3)
Plz explain...
find the equation of the line passing through (-2,3) and the centre of the circle. the centre is the mid-point of the line segment joining (-2,3) and the inverse point
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