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The inverse point of (-2,3) with rspect to circle x^2+y^2-4x-6y+9=0 is a)(1,1) b)!1,2) c)(1,3) d)(2,3) Plz explain...

The inverse point of (-2,3) with rspect to circle x^2+y^2-4x-6y+9=0 is


a)(1,1)


b)!1,2)


c)(1,3)


d)(2,3)


  Plz explain...

Grade:12

1 Answers

Chetan Mandayam Nayakar
312 Points
10 years ago

find the equation of the line passing through (-2,3) and the centre of the circle. the centre is the mid-point of the line segment joining (-2,3) and the inverse point

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