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question mark

The inverse point of (-2,3) with rspect to circle x^2+y^2-4x-6y+9=0 is

a)(1,1)

b)!1,2)

c)(1,3)

d)(2,3)

Plz explain...

Chilukuri Sai Kartik , 14 Years ago
Grade 12
anser 1 Answers
Chetan Mandayam Nayakar

find the equation of the line passing through (-2,3) and the centre of the circle. the centre is the mid-point of the line segment joining (-2,3) and the inverse point

Last Activity: 14 Years ago
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