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if the line y=√3 x cuts the curve x4 + ax2y +bxy+cx+dy+6=0 at A,B,CandD then OA.OB.OC>OD(where O is the origin) is?

ans. 96

Pranjal gupta , 15 Years ago
Grade
anser 1 Answers
Chetan Mandayam Nayakar

x4+√3ax3+√3bx2+cx+√3dx+6=0,,x1,x2,x3,x4,are the four roots,OA=sqrt(x1^2+y1^2)=sqrt(x1^2+3x1^2)=2x1,OB=2x2, OC=2x3, OD=2x4, OA.OB.OC.OD=16X1*X2*X3*X4=16*6=96

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