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r = 3 , last term = 486 , sum = 728
last term = arn-1 = 486 ..................1
sum = a(rn - 1)/r-1 = 728 ................2
divide both
728/486 = (rn-1)/[(r-1)(rn-1)
r = 3 so
728/486 = 3n-1/2x3n-1
729 - 1 / 243 = 3n - 1 /3n-1
36 - 1 / 35 = 3n - 1 / 3n-1
comparing both sides we get
n = 6 or n-1 = 5
total terms = 6
from eq 1 , arn-1 = 486
a 35 = 486 = 243x2 = 35x2
a = 2
firat term is 2 & total terms are 6 ,
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Hello Sir,
Please give me the answer for this question from Arithmetic Progression.
Insert a A.M. between 5 and 20.
Anitha.
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