vikas askiitian expert
Last Activity: 13 Years ago
centroid of triangle = [ x1+x2+x3/3 , y1+y2+y3/3 ]
centroid = [ (1+cost+sint)/3 , (2+sint -cost)/3 ] = (x,y) ..................1
from eq 1
3x = 1 + cost + sint
(3x-1) = sint + cost ..................2
3y = 2 + sint - cost
(3y-2) = sint - cost ............... 3
now applying , (eq 2)2 + (eq3 )2
(3x-1)2 + (3y-2)2 = 2
this is equation of circle