If a&b are the eccentricities of the hyperbolas xy=-25 and x^2-y^2=16 then(a+b)^2 equals. (1)2 (2)4 (3)8 (4)6 {*plese explen*}

Question

PRIYANKA TATA ASKIITIAN · Answer

the above hyperbolas represent rectangular hyperbolas...so the eccentricity is always √2.

=> a=b=√2

(a+b)²= (2√2)² = 8

hence the answer is option 3.

plz approve my ans..

priyanka tata

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If a&b are the eccentricities of the hyperbolas xy=-25 and x^2-y^2=16 then(a+b)^2 equals. (1)2 (2)4 (3)8 (4)6 {plese explen}

If a&b are the eccentricities of the hyperbolas xy=-25 and x^2-y^2=16 then(a+b)^2 equals. (1)2 (2)4 (3)8 (4)6 {plese explen}

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If a&b are the eccentricities of the hyperbolas xy=-25 and x^2-y^2=16 then(a+b)^2 equals. (1)2 (2)4 (3)8 (4)6 {*plese explen*}

If a&b are the eccentricities of the hyperbolas xy=-25 and x^2-y^2=16 then(a+b)^2 equals. (1)2 (2)4 (3)8 (4)6 {*plese explen*}

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If a&b are the eccentricities of the hyperbolas xy=-25 and x^2-y^2=16 then(a+b)^2 equals. (1)2 (2)4 (3)8 (4)6 {plese explen}

If a&b are the eccentricities of the hyperbolas xy=-25 and x^2-y^2=16 then(a+b)^2 equals. (1)2 (2)4 (3)8 (4)6 {plese explen}