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The locus of the mid-points of the chords of x^2 + y^2 + 4x - 6y -12 =0 which subtend an angle of pi/3 at its circumference is (1){x-2}^2 + {y+3}^2=6.25 (2){x+2}^2 + {y-3}^2=6.25 (3){x+2}^2 + {y-3}^2=6.25 (4){x+2}^2 + {y+3}^2=6.25{*plese explen*}

9 years ago

Answers : (2)

Nishant Vora
IIT Patna
askIITians Faculty
2467 Points
							223-2477_2.PNG
						
5 years ago
Ravi
askIITians Faculty
69 Points
							Only equal chords subtend equal angles at the centre. Find the distance between centre of circle and the mid point of chord. The locus will be a circle woth same centre and radius equal to the the distance between centre and the mid point.
Also, the angle subtend at the centre is pi/3. So, equilateral triangle is formed among the 2 radii arms and the chord. Use this information to find the length of perpendicular (length of altitude in an equilateral triangle.)
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5 years ago
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