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Find the equation of the line perpendicular to 2x-3y+5=0 which is at a distance of 5 units from the origin.


PLEASE REPLY SOON.


Thanks

8 years ago

Answers : (2)

SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

slope of this line is  2/3

hence slope of perp line is -3/2

now find its equation....

8 years ago
Pramod J AskiitiansExpert-IIT-B
36 Points
							

Dear student

slope of the given line is = 2/3

slope of line perpendicular to this = -3/2

so the required equation of line is = y = -3x/2 + c

perpendicular distance from origin = 

=> d = 5 = | c/(13^1/2)|

=> c = + or - 5*(13^1/2)

i hope it explains

8 years ago
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