Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the equation of the line perpendicular to 2x-3y+5=0 which is at a distance of 5 units from the origin. PLEASE REPLY SOON. Thanks

Find the equation of the line perpendicular to 2x-3y+5=0 which is at a distance of 5 units from the origin.


PLEASE REPLY SOON.


Thanks

Grade:

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

slope of this line is  2/3

hence slope of perp line is -3/2

now find its equation....

Pramod J AskiitiansExpert-IIT-B
36 Points
10 years ago

Dear student

slope of the given line is = 2/3

slope of line perpendicular to this = -3/2

so the required equation of line is = y = -3x/2 + c

perpendicular distance from origin = 

=> d = 5 = | c/(13^1/2)|

=> c = + or - 5*(13^1/2)

i hope it explains

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free