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Find the equation of the line perpendicular to 2x-3y+5=0 which is at a distance of 5 units from the origin.
PLEASE REPLY SOON.
Thanks
Dear student,
slope of this line is 2/3
hence slope of perp line is -3/2
now find its equation....
Dear student
slope of the given line is = 2/3
slope of line perpendicular to this = -3/2
so the required equation of line is = y = -3x/2 + c
perpendicular distance from origin =
=> d = 5 = | c/(13^1/2)|
=> c = + or - 5*(13^1/2)
i hope it explains
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