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the cojugate of complex number 3+2j is?
1)3-2j
2)2+3j
3)2-3j
4)3+4j
3-2i
z = 3 + 2i
conjugate of z = 1/z
conjugate z = 1/3+2i
multiplying & dividing by 3-2i
= (3-2i/9-4i2)
i2 = -1 so
conjugate = 3-2i/13
=3/13 - 2i/13
this is the required ans
approve if u like this ans
dear vikrant ,
i have solved for mulltiplicative inverse , that is multiplicative inverse nor conjugate ...
z = x + iy then conjugate is
conjugate = x - iy
real part remains same but sign of imajinary part is reversed...
Dear Vikrant ,
to find the conjugate of a complex number a + ib all we need to do is to change the '+' symbol to '-' and if the given complex number is a-ib , we change the '-' to a '+'.
So following that rule
given complex number z = 3 + 2j
so the conjugate of this number is
3 - 2j
option (1) is your answer
Please approve
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