If triangle AOB is an equilaterlal triangle (O is the and A is a pointon the x axis ) then the centriod of the triangle will be

ASSUMING O IS THE ORIGIN:

A IS DISTANCE a UNITS FROM THE ORIGIN.coordinate of A is (a,0)

coordinate of b is (a/2,3^1/2a/2)...easily attainable....u knw that ob makes an angle of pi/3 with x axis and that the distance of ob is a units......

NOW, THE X COORDINATE OF CENTROID IS a/2. from symetry.

or now u knw the points u can find centroid usin- g=((x₁+x₂+x₃)/3,(y₁+y₂+y₃)/3)