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LINE L1-Y-X=0,;L2=2X+Y INTERSECT L3.;Y+2=0 AT P AND Q
THE BISECTOR OF ACUTE ANGLE BETWEEN L1 AND L2 INTERSECT
L3 AT R.. IS THE FDOLLOWING STATEMENT TRUE OR NOT IF YES WHY??
THE RATIO OF PR:RQ IS 2ROOT2:ROOT5??
eqn of d angle bisector will b (|y-x|)/root2=(|y+2x|)/root5
logically it can b seen d eqn of d acute angle bisector will be: (y-x)/root2=(y+2x)/root5 (1) [removin mod sign]
thus d pt R can b obtained by solving(1) and y=-2 which will give [(-2)(root5-root2)/2root2+root5),-2]
P(-2,-2), Q(1,-2)
now find out PR nd RQ as we know deir coordinates
on solvingPR:RQ comes out to b 2root2:root5,hence d statement is true
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