MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        


Can you help solve this problem?


Q. Prove the locus of the centre of the circle


1/2(x*x+y*y) +xcosa + ysina -4 =0 is x*x+y*y=1


7 years ago

Answers : (3)

vikas askiitian expert
510 Points
							

1/2(x2+y2) + xcosa + ysina - 4 = 0

x2+y2 + 2xcosa + 2ysina - 8 =0

coordinates of center = (h,k) = (-g,-f)

 g = cosa , f=sina             (from eq of circle)

(h,k) = (-cosa, -sina)

h = -cosa , k = -sina

h2 + k2 = (-cosa)2 + (-sina)2

            =sin2a+cos2a=1

h2 + k2 = 1

replacing (h,k) by (x,y)

x2+y2 = 1           

this is the required equation

approve my ans if u like it

7 years ago
ANAM V. RANGA REDDY
24 Points
							

Let center of the circle be (h, k) .

center of given circle=(-cos a, -sin a)

(-cos a, -sin a) =(h, k) → h = cos a and k = -sin a

cos2a + sin2a = 1 → h2+k2= 1

locus of (h,k) is x2+y2=1

7 years ago
Rohit G
31 Points
							

Thank you sirs. 

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 53 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details