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Grade: 10
        number of ways of selecting two numbers from 1 to 12 such  that  their  sum  is divisible by 3.
10 years ago

Answers : (3)

Pratham Ashish
17 Points
							

Dear Naveen

for a no to be divisible by 3 , possibilities are 3,6,9,15,18,21

if 2 no. are x and y , den

eqns are

x + y = 3 ,x + y = 6, x + y = 9, x + y = 12 , x + y = 15 , x + y = 18 , x + y = 21

for 1st eqn x,y wud be 1 & 2

for 2nd set is (2,4),(1,5)

for 3rd (1,8),(2,7),(3,6),(4,5)

for 4th (1,11),(2,10),(3,9),(4,8),(5,7),(6,6)

for 5th (12,3),(11,4),(9,6),(10,5),(8,7)

for 6th (12,6),(11,7),(10,8)

for 7th (10,11)

just count the possibility and dat is ur ans

10 years ago
Harpreet Kaur Oberoi
18 Points
							

12

10 years ago
saumendra aggarwal
8 Points
							48
						
9 years ago
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