Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
number of ways of selecting two numbers from 1 to 12 such that their sum is divisible by 3.
Dear Naveen for a no to be divisible by 3 , possibilities are 3,6,9,15,18,21 if 2 no. are x and y , den eqns are x + y = 3 ,x + y = 6, x + y = 9, x + y = 12 , x + y = 15 , x + y = 18 , x + y = 21 for 1st eqn x,y wud be 1 & 2 for 2nd set is (2,4),(1,5) for 3rd (1,8),(2,7),(3,6),(4,5) for 4th (1,11),(2,10),(3,9),(4,8),(5,7),(6,6) for 5th (12,3),(11,4),(9,6),(10,5),(8,7) for 6th (12,6),(11,7),(10,8) for 7th (10,11) just count the possibility and dat is ur ans
Dear Naveen
for a no to be divisible by 3 , possibilities are 3,6,9,15,18,21
if 2 no. are x and y , den
eqns are
x + y = 3 ,x + y = 6, x + y = 9, x + y = 12 , x + y = 15 , x + y = 18 , x + y = 21
for 1st eqn x,y wud be 1 & 2
for 2nd set is (2,4),(1,5)
for 3rd (1,8),(2,7),(3,6),(4,5)
for 4th (1,11),(2,10),(3,9),(4,8),(5,7),(6,6)
for 5th (12,3),(11,4),(9,6),(10,5),(8,7)
for 6th (12,6),(11,7),(10,8)
for 7th (10,11)
just count the possibility and dat is ur ans
12
48
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -