Analytical Geometry
x^2+y^2=1/4 and (x+1/2)^2+y^2+z^2=1...Then how does one get from second equation -1<=z<=1..
x^2+y^2=1/4 and (x+1/2)^2+y^2+z^2=1...Then how does one get from second equation -1<=z<=1..
1 Answer
Askiitians_Expert Yagyadutt
hello darshana
your question is not clear...please make it more clear what to find out
(x+1/2)^2+y^2+z^2=1 this is equation of a sphere...with limitation on z as given by -1 <= z <=1
and x^2 + y^2 = 1/4 is equation of a circle ...
now what to do ?
i will post the solution after u make it clear okk !
Regards
yagya
askiitians_expert
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