Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the equation of ellipse whose centre is C(4,3) and focus S(2,3) eccentricity e=1/2[.5] Is this a case of tilted ellipse ? Plz explain the solution Askiitians_Expert Yagyadutt
11 years ago

Hello Vinay

As u see the C and S has common y-co-ordinate..it means both C and S lies on same line y=3
So y=3 is the major axis...

Distance between CS = ae (distance between two focus is 2ae)

CS = 2

So ae = 2

a = 4

Now  e^2 = 1 - (b/a)^2   => 1/4 = 1 - ( b/4)^2

=> (b/4)^2 = 3/4

b/4 = root(3)/2

b= 2.root(3)

Equation when center is (h,k) with and major axis with a ( a>b) and minor with b..

(x-h)^2/b^2 + (y-k)^2/a^2 = 1

and if b>a  then  (x-h)^2/a^2 + (y-k)^2/b^2 = 1

=> (x-4)^2/4 + (y-3)^2/12 = 1   ans,

With regards

Yagya