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A line 3x+4y-5=0 cus the curve 2x^2 + 3y^2=5 at P and Q. Find angle POQ where O is the origin.

Anil Pannikar AskiitiansExpert-IITB · Accepted Answer

Dear Karthik,SUbstitute value of x from the line into the curve and find out y and then x. Now find the slope of PO and QO by relation - slope = y2-y1/x2-x1Now u have 2 slopes m1 and m2Use the formula tan&theta; = mod. ( m1-m2/1+m1m2)Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.All the best.Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..Askiitians ExpertAnil PannikarIIT Bombay

Analytical Geometry> Urgent...

A line 3x+4y-5=0 cus the curve 2x^2 + 3y^2=5 at P and Q. Find angle POQ where O is the origin.

Karthik Eyan , 14 Years ago

Anil Pannikar AskiitiansExpert-IITB

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Analytical Geometry> Urgent...

A line 3x+4y-5=0 cus the curve 2x^2 + 3y^2=5 at P and Q. Find angle POQ where O is the origin.

Karthik Eyan , 14 Years ago

Anil Pannikar AskiitiansExpert-IITB

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

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