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find the equation of a circle which passes through the origin and cuts off chords of length 4 and 6 on the positive x axis and y axis resp
let equation of circle be x^2 +y^2 +2gx+2fy+c.............eq1
as circle passes through origen therefore c=0
x intersept is given by 2(g^2-c)^1/2 =4
y intersept is given by 2(f^2-c)^1/2 =6
we get (g,f)=(+_2,+_3)
now eq1 becomes
x^2 + y^2 +_4x +_6y =0 is the required circle
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