the line x+y=a meets x&y axes at A&B.A triangle AMN is inscribed in the triangle OAB,O being origin with right angle at N.M&N lie respectively on OB & AB.If area of AMN is 3/8 of area of triangle OAB then AN/BN

Dear gayatri,

The line x+y=a meets x&y axes at A&B.A triangle AMN is inscribed in the triangle OAB

Then by solving analytically we get,

AN/BN=2/3

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