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Find the equation of the bisector of the angle between 4x+y-7=0 and x-4y+3=0 which contains the origin.

Find the equation of the bisector of the angle between 4x+y-7=0 and x-4y+3=0 which contains the origin.

Grade:12

2 Answers

A S
36 Points
10 years ago

Dear Aditya,

Suppose we have two equations ax++by+c=0 and px+qy+r=0. First we make c and r positive. Then equations of bisectors are-

955_17036_temp.jpg

For bisector containing origin, + sign is used and - sign for the other.

For your question, this method could be used.

Post all your doubts here. Kindly approve the answer if you like it.

Best of Luck!

Regards,

A S

Nehal Wani
21 Points
10 years ago

The Bisector Of These Lines Passes Through The Point Of Intersection Of These Lines As Well As Origin.

4x+y-7=0

    or

16+4y-28.......................(i)

x-4y+3=0........................(ii)

Solving (i) and (ii)

We get:

x=25/17 and y=19/17

The Required Line Passes Through (0,0) and (25/17,19/17)

Therefore Equation:

19y-25x=0

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