Equation of a curve that would cut x2 + y2 - 2x - 4y - 15 = 0 orthogonally can be ?

Dear Rishi,

Any line passing through the centre of the given circle would meet the circle orthogonally. Hence the equation of such curve would be given as :

             (y-2) = lamda(x-1): where as lamda belongs to R.

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