Three distinct points A, B and C are given in the 2 – dimensional coordinate plane such that the ratio of
the distance of any one of them from the point (1, 0) to the distance from the point (–1, 0) is equal to
3 1
.
Then the circumcentre of the triangle ABC is at the point -

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SHAIK AASIF AHAMED · Answer

Your question is not clear and seems to be incomplete. Please recheck your question andpost it again. Thanks and Regards Shaik Aasif askIITians Faculty

Sarthak tomar · Answer

The answer is (5/4, 0) That's the circumcenter of the triangle abc by solving through simple distance formula

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Three distinct points A, B and C are given in the 2 – dimensional coordinate plane such that the ratio of the distance of any one of them from the point (1, 0) to the distance from the point (–1, 0) is equal to 3 1 . Then the circumcentre of the triangle ABC is at the point -

Three distinct points A, B and C are given in the 2 – dimensional coordinate plane such that the ratio of
the distance of any one of them from the point (1, 0) to the distance from the point (–1, 0) is equal to
3 1
.
Then the circumcentre of the triangle ABC is at the point -

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Three distinct points A, B and C are given in the 2 – dimensional coordinate plane such that the ratio of the distance of any one of them from the point (1, 0) to the distance from the point (–1, 0) is equal to 3 1 . Then the circumcentre of the triangle ABC is at the point -

Three distinct points A, B and C are given in the 2 – dimensional coordinate plane such that the ratio of the distance of any one of them from the point (1, 0) to the distance from the point (–1, 0) is equal to 3 1 . Then the circumcentre of the triangle ABC is at the point -

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Three distinct points A, B and C are given in the 2 – dimensional coordinate plane such that the ratio of
the distance of any one of them from the point (1, 0) to the distance from the point (–1, 0) is equal to
3 1
.
Then the circumcentre of the triangle ABC is at the point -