There are 11 chairs in a row. There are 3 boys and 5 girls. Find the number of arrangements such that no 2 boys sit together-

Question

Riddhish Bhalodia · Answer

First we arrange the boys. we remove 3 chairs
there are 9 gaps in the 8 remaining chairs where the 3 chairs of the boys can be arranged in $^9C_3.3!$ ways

then the remaining girls can be arranged in
$^8C_5.5!$
so the total number of ways is
$^8C_5.5! \times ^9C_3.3!$

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There are 11 chairs in a row. There are 3 boys and 5 girls. Find the number of arrangements such that no 2 boys sit together-

There are 11 chairs in a row. There are 3 boys and 5 girls. Find the number of arrangements such that no 2 boys sit together-

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There are 11 chairs in a row. There are 3 boys and 5 girls. Find the number of arrangements such that no 2 boys sit together-

There are 11 chairs in a row. There are 3 boys and 5 girls. Find the number of arrangements such that no 2 boys sit together-

1 Answers

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Other Related Questions on Algebra

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