Flag Trigonometry> the mean and the standard deviation of a ...
question mark

the mean and the standard deviation of a data of 8 items are 25 and 5 respectively. If two items 15 and 25 are added to this data, then the variance of the new data is

Mahesh , 5 Years ago
Grade 12
anser 1 Answers
Samyak Jain

Last Activity: 5 Years ago

Ans. is 8.
We know that formula of variance is [∑(xi – \mu)2 ] / N, where i = 1,2, …, N , 
                   xi are observations,  \mu is mean, N is number of observations.
Solving this we get variance = [∑xi2 – N\mu2] / N  =  (∑xi2 / N) – \mu2 and standard deviation is square root of variance.
Initial mean (\mu1) = 25 = ∑xi / 8  
Initial standard deviation (\sigma) = 5  \Rightarrow  Initial variance (\sigma2) = 52 = 25 = (∑xi2 / 8) – \mu12 
\therefore  25 = (∑xi2 / 8) – 252   or   (∑xi2 / 8) = 25 + 625 = 650
∑xi2 = 650 x 8 = 5200.
 
Now, finally there are 10 items. 
Final mean, \mu2  = (\mu1 x 8 + 15 + 25) / 10 = (25 x 8 +15 + 25) / 10 = 240 / 10  =  24.
Final variance = (final ∑xi2 / final N) – \mu2  =  {(5200 + 152 + 252) / 10} – 242 
                       =  {(5200 + 225 + 625) / 10} – 576
                       =  605 – 576
                       =  29.

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...