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The fourth term of an AP is 4. Then the sum of the first 7 terms is
t4= 4 a + 3d = 4 S7= 3.5 x [2a + 6d] S7= 7 (2)(a+3d) = 7(2)(4) S7= 28Thanks & RegardsBharat Bajajaskiitian facultyIIT Delhi
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