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The condition for the cube of a+ib to be a real number is (i) a=0 or a=+/- Root 3b (ii) a=0 or b=+/- Root 3a (iii) b=0 or b=+/- Root 3a (iv) b=0 or a=+/- Root 3b

The condition for the cube of a+ib to be a real number is
  • (i) a=0 or a=+/- Root 3b 
  • (ii) a=0 or b=+/- Root 3a
  • (iii) b=0 or b=+/- Root 3a
  • (iv) b=0 or a=+/- Root 3b

Grade:11

1 Answers

Deepak Kumar Shringi
askIITians Faculty 4404 Points
6 years ago
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