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Grade 12th passAlgebra

The answer is option c can someone please explain how it can be solved? 13568293639976662221111111111111111111111111111(writing anything to complete the 50 characters limit)

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Anushka Mishra

8 Years agoGrade 12th pass

1 Answer

Ritesh Khatri

8 Years ago

$[sinx + cosx] = [\sqrt{2}sin(\frac{\pi}{4}+x)]$

Now for x belongs to 0 to Pi/4 (=0.785)

$[\sqrt{2}sin(\frac{\pi}{4}+x)] = 1$

LHS = 1

for x belongs to 0 to Pi/4 (=0.785)

[-sinx] = -1

[-cosx] = -1

RHS = 3-1-1 = 1

Therefore for all values between 0 and 0.785 above expression is true.

Similarly we can check for remaining range

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