Solve the following pair of linear equations by the substitution method √2 x+√3 y = 0√3 x-√8 y = 0

Dear Student


Given,
√2 x + √3 y = 0
and
√3 x - √8 y = 0
are the two equations.
From 1st equation,
we get,
x = - (√3/√2)y __________________(1)
Putting the value of x in the given second equation to get,
√3(-√3/√2)y - √8y = 0
⇒ (-3/√2)y- √8 y = 0
⇒ y = 0

Now, substitute the value of y in equation (1),
we get,
x = 0
Therefore, x = 0 and y = 0 is required solution.

Thanks