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question is in the image

Aman Gandhi , 10 Years ago

Grade 12

1 Answers

Nishant Vora

Last Activity: 10 Years ago

Hello Student, Please find the solution
A= log m + log n
=> A= log (mn)
=> $A= \log_{10} (\frac{(ab)^2 - [(ab)^2 - 4(a+b)]}{4})$

$A= \log_{10} [\frac{ 4(a+b)}{4}]$

$A= \log_{10} [\frac{ 4(43+57)}{4}] = \log_{10} 100 = 2$

Now, $B= 2^{\log_{6} 18} 3^{\log_{6} 3}$

$B= 2^{\log_{6} 6*3} 3^{\log_{6} 3}$

$B= 2^{\log_{6} 6+ \log_{6}3} 3^{\log_{6} 3}$
$B= 2^{1+ \log_{6}3} 3^{\log_{6} 3}$
$B= 2*2^{\log_{6}3} 3^{\log_{6} 3}$
$B= 2*6^{\log_{6}3}$
$B= 2*3 =6$

So A*B = 6*2 = 12

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