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Grade: 12th pass
        
Please solve the question in the attachment 
........ .. .................. . 
5 months ago

Answers : (3)

Khimraj
2914 Points
							
since adj(adj(X)) = X
so  C = A
and B = D = adj(A)
and
adj(adj(adj(adj(ABCD)))) = ABCD = ABAB = A*adj(A)*A*adj(A)
since A*adj(A) = |A| 
so adj(adj(adj(adj(ABCD)))) = |A|*|A| = |A|2
so k=2
Hope it clears.......................
 
5 months ago
Pawan joshi
26 Points
							
 sir answer is not 2.
5 months ago
Khimraj
2914 Points
							
sorry
since A*adj(A) = |A| *I
|adj(adj(adj(adj(ABCD))))| = |(|A|*I)(|A|*I)| = ||A|*I|*||A|*I| = 0*0 = 0
so |adj(adj(adj(adj(ABCD))))| = |A|^{-\infty }
So k = {-\infty }
Hope now it is correct
5 months ago
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