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Past exam paper. Which needs answers. Help is appreciated very much. Thank you all in advannce

Past exam paper. Which needs answers.            Help is appreciated very much. Thank you all in advannce

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Grade:12th pass

1 Answers

Aditya Gupta
2081 Points
4 years ago
hello njini, plz ask 1 ques in a thread.
so i ll ans your 1st ques.
let J= ∫dp/(3 – 4sinp + 2cosp) from 0 to pi
this can be easily solved by substituting t= tan(p/2) so that 2dt/dp= sec^2(p/2)= 1+ tan^2(p/2)= 1+t^2 and using the standard formulas:
sinp= 2t/(1+t^2) and cosp= (1 – t^2)/(1+t^2)
so putting in all these values you shall obtain a quad expression in denominator which can be factorised and converted to partial fractions to obtain the final ans as:
 – 0.71484 approx
kindly approve :=)

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