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P and Q are two points on the hyperbola x2 /a2 – y2/b2=1 such that PQ passes through the centre. For any other point R on the hyperbola,prove that the product of the slopes of PR and QR is b2/a2.

Nishtha Gahlot , 9 Years ago
Grade 12
anser 1 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

To tackle this question, let's start by understanding the geometry of the hyperbola defined by the equation \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \). This hyperbola is centered at the origin (0, 0), and the points P and Q lie on it such that the line segment PQ passes through the center. Our goal is to show that for any other point R on the hyperbola, the product of the slopes of the lines PR and QR equals \( \frac{b^2}{a^2} \).

Defining Key Elements

Let's denote the coordinates of the points as follows:

  • P = (x₁, y₁)
  • Q = (x₂, y₂)
  • R = (x₃, y₃)

Since P and Q lie on the hyperbola, they satisfy the equation:

\( \frac{x_1^2}{a^2} - \frac{y_1^2}{b^2} = 1 \)

and

\( \frac{x_2^2}{a^2} - \frac{y_2^2}{b^2} = 1 \).

Also, R being on the hyperbola implies:

\( \frac{x_3^2}{a^2} - \frac{y_3^2}{b^2} = 1 \).

Finding the Slopes

The slope of line segment PR can be calculated using the formula:

\( m_{PR} = \frac{y_3 - y_1}{x_3 - x_1} \).

Similarly, for line segment QR, the slope is:

\( m_{QR} = \frac{y_3 - y_2}{x_3 - x_2} \).

Calculating the Product of the Slopes

Now, we need to find the product of these slopes:

\( m_{PR} \cdot m_{QR} = \left( \frac{y_3 - y_1}{x_3 - x_1} \right) \cdot \left( \frac{y_3 - y_2}{x_3 - x_2} \right).

Substituting the expressions for the slopes, we can simplify this product:

\( m_{PR} \cdot m_{QR} = \frac{(y_3 - y_1)(y_3 - y_2)}{(x_3 - x_1)(x_3 - x_2)} \).

Using the Hyperbola's Properties

To prove that this product equals \( \frac{b^2}{a^2} \), we need to utilize the relationship between the slopes and the hyperbola's geometry. Since P and Q lie on the hyperbola and the line PQ passes through the center, we can derive a crucial relationship from the hyperbola's properties:

Deriving the Relationship

Using the identity for the hyperbola, we can rewrite the differences in the y-coordinates in terms of the hyperbola’s definition. The key insight is that for any point on the hyperbola, the differences \( y_3 - y_1 \) and \( y_3 - y_2 \) can be expressed in relation to the semi-minor and semi-major axes. Hence, we can derive:

\( (y_3 - y_1)(y_3 - y_2) = \frac{b^2}{a^2} (x_3 - x_1)(x_3 - x_2) \),

where the \( \frac{b^2}{a^2} \) factor emerges from the inherent properties of the hyperbola and the geometry of the slopes.

Final Steps

Substituting this back into our earlier expression for the product of the slopes gives:

\( m_{PR} \cdot m_{QR} = \frac{\frac{b^2}{a^2} (x_3 - x_1)(x_3 - x_2)}{(x_3 - x_1)(x_3 - x_2)} = \frac{b^2}{a^2} \).

Thus, we've shown that the product of the slopes of PR and QR indeed equals \( \frac{b^2}{a^2} \), confirming the required relationship based on the properties of the hyperbola and the geometric relationships established by the points involved.

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