Number of seven digit natural numbers in which both 2 and 3 are present as digits if no two 2’s are consecutive in any number is\t26\t33\t32\t53

I am assuming that 2 and 3 are the only digits present otherwise among these there is no answer
We need to consider cases
When there are 3 3’s and 4 2’s ( As more than 4 2’s two 2’s will be together)
Only 1 case
4 3’s and 3 2’s
Fix 3’s at 4 alternate positions and 3 2’s will have 5 positions as shown
_3_3_3_3_
Conitnue like this by increasing number of 3’s till 6 you will get the answer.

If there is any confusion, please let me know.